If x+y+z= 8 and x y + y z + z x = 26, find the value of x3+ y3+ z3
RG416:
it should be X2+y2+z2
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Answer:
6.(a + b + c)3= a3+ b3 + c3+3a2b+3a2c + 3b2c +3b2a +3c2a +3c2a+6abc.
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