if x+y+z=8 and xy+yz+zx =13 , then find the value of x²+y²+z²
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Step-by-step explanation:
(x+y+z)² = x2+y²+z² +2(xy+yz+ zx)
8² = x²+y²+z²+2(13)
x²+y²+z² = 64-26 = 38
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