Question

If x(y+z)=88, y(z + x) = 100, z(x + y) = 108 then yz=.. A) 78 B) 88 C) 60 D) 272​

Answer 1

Step-by-step explanation:

xy+xz = 88 (1)

yz+xy = 100 (2)

xz+zy = 108 (3)

Adding (2) and (3) and subtracting (1)

2yz = 108+100-88

2yz = 120

yz = 60

Option C

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Answer 2

Answer:

if x(y+z)=88,y(z+x)=100,z(x+y)=108 then yz=C)60