if x+y+z=9, xy+yz+zx=26 and xyz=24, find the value of x²(y+z) + y²(z+x) + z²(x+y)
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Answered by
1
Answer:
63
Step-by-step explanation:
[x+y+z] ^2 =x ^2 +y ^2 +z ^2+2[xy+yz+zx]
9 ^2=x ^2+y ^2 +z ^2 +2(9)
∴x ^2 +y ^2 +z ^2
=63
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