Question

If x+y+z=90
and x+a=50
and a+z+b=80
then find,
y+b+b=?​

Answer 1

Answer:

90

Step-by-step explanation:

x+y+z=90

x=30,y=30,z=30,

X+a=50

30+20=50.

so a=20.

a+z+b=80

20+30+30=80.

so b=30

y+b+b=?

30+30+30=90

Answer 2

Answer:

in 1st condition X=30,y=30,z=30

therefore, X+y+z=90

30+30+30=90

in 2nd condition,

now,X=30 so,

X+a=50

30+a=50

a=50-30

a=20

in 3rd condition,

a+z+b=80

20+30+b= 80

50+b=80

b=80-50

b=30

Now, y+b+b=?

30+30+30=90