Question

if x-y-z and xy=3,xz=9 the yz=​

Answer 1

Step-by-step explanation:

x-y-z = 0

xy = 3 --->1

xz = 9 --->2

subtract 2 from 1

xy-xz = 3-9

x(y-z) = -6

from x-y-z =0,y-z = -x

==> x*(-x) = -6

==> -x^2 = -6

==> x = √6

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