Question

if x, y, z are 3 integers such that x+y=8, y+z=13, z+x=17 then the value of x²/yz is ? ​

Answer 1

Given, x+y=8, y+z=13 and z+x=17x^2/yz=?

y+z-(x+y)=13–8 =>z-x=5

Again x+z+x=5+17=>2z=22 =>z=11

Putting z in z+x and y+z we get 11+x=17 y+11=13x=6 and y=2

Therefore, x^2/yz=36/11*2 x^2/yz=18/11=