If x, y, z are in A.P., prove that
zx+xy /yz, + xy+yz/zx, + yz+zx/xy
are also in A.P.
Answers
Answered by
6
Answer:
x, y, z are in A.P
⇒2y=x+z
∴xy+yz+zx=x(
2
x+z
)+(
2
x+z
)z+zx
=
2
x
2
+xz
+
2
xz+z
2
+zx
=
2
x
2
+z
2
+4zx
.
∴xy+yz+zx=
2
x
2
+z
2
+4zx
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