Question

if x, y, z are in A. P then e^-x, e^-y, e^-z are in
1)in A. P
2)in G. P
3)equal
4)no definite sequence
Pls answer with solution
A bit faster

Answer 1

[0010001111]... Hello User... [1001010101]
Here's your answer...

If x, y, z are in AP, then 2y = x+z

Now, lets try the options.

(2nd option is correct, if you're in a hurry, btw)

If e^-x, e^-y, e^-z are in GP, then (e^-y)² = e^-x × e^-z
e^-2y = e^-(x+z)
Comparing the powers,
-2y = -(x+z)
2y = x+z, which keeps in with the question.

So the numbers are in GP.

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