If x,y,z are in continued proportion prove-:.....Question is given in picture question no.20.....Thnk u
Attachments:
Answers
Answered by
5
since , x , y , z are in continued proportion
hence , x : y :: y : z
=> x/y = y/z
=> y² = xz
LHS = (x+y)² / (y+z)²
=> (x²+y²+2xy) / (y²+z²+2yz)
=> (x²+xz+2xy) / (xz+z²+2yz). (as , y² = xz)
=> x (x+z+2y) / z (x+z+2y)
(x+z+2y) gets cancelled out
=> x / z
RHS = x / z
since , LHS = RHS
Proved
hope this helps
hence , x : y :: y : z
=> x/y = y/z
=> y² = xz
LHS = (x+y)² / (y+z)²
=> (x²+y²+2xy) / (y²+z²+2yz)
=> (x²+xz+2xy) / (xz+z²+2yz). (as , y² = xz)
=> x (x+z+2y) / z (x+z+2y)
(x+z+2y) gets cancelled out
=> x / z
RHS = x / z
since , LHS = RHS
Proved
hope this helps
Similar questions
English,
8 months ago
Political Science,
8 months ago
Social Sciences,
8 months ago
English,
1 year ago