Question

If x, y, z are in G.P. and (x+1), (y+6), 2+3) are in ap x+y+z=26, then find the values of x,y,z .​

Answer 1

Answer:

Step-by-step explanation:

Since z−y=y−x. x+z=2y and hence 3y=21. So, y=7.

x+z=2y=14. So, z=14−x.

For any value of x, x,7,14−x are in A.P.

If a natural number means a positive integer, them x can take the values 1,2,3,…,13.