Math, asked by prii35, 11 months ago

If x, y, z are positive integers, such that xy + x + y = 215, yz + y + z = 161 and Zx + 2 + x = 107, then (y - Z)/(x - 2) =

Answers

Answered by rashad91
0

Answer:

23*8+23+8=2l5

xy+x+y=2l5

8*l7+8+l7=l6l

yz+y+z=l6l

x=23

y=8

z=l7

third wrong

-9/2l last

Answered by rknath95
2

Answer:

3

Step-by-step explanation:

x=11

y=17

z=8

11*17+11+17 = 215

17*8+17+8 = 161

8*11+8+11 = 107

(y-z)/(x-z)=?

(17-8) / (11-3)= 9/3 = 3

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