Question

If x y z are positive real numbers suct that xyzw=1 and find the (x+1)(y+1)(z+1)(w+1)

Answer 1

[(x+1)(y+1)][(z+1)(w+1)]
[(xy+x+y+1)][(zw+z+w+1)]
xyzw+zx+wx+yz+yw+1
2+zx+wx+yz+yw
-2=zx+wx+yz+yw
This ur answer.
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