Question

if x,y,z are positive variables and the value of (x+y+z)=18, then what is the maximum value of xyz? a. 110 b. 100 c. 216 d. 252

Answer 1

Answer: Option 'C' is correct.

Explanation:

Since we have given that

$x+y+z=18$

Now, we want to find the maximum value of xyz

Then , it must be x=y=z

So, our equation becomes,

$x+y+z=18\\\\x+x+x=18\\\\3x=18\\\\x=\frac{18}{3}\\\\x=6$

so,

$xyz=6\times 6\times 6=216$

Hence ,Option 'C' is correct.

Answer 2

X+Y+Z=18

MAX. VALUE OF X.Y.Z WHEN X=Y=Z

THEREFORE:X+X+X=18

3X=18

X=6

MAXIMUM VALUE=6*6*6

=216