Question

If x,y,z are the three natural number whose sum is divisible by 6.Show that x^3+y^3+z^3 is divisible by 6?

Answer 1

I know you have asked it a long time ago but i am answering this to helps you

Proof:

Let the 3 numbers be 1,2&3

Then,

1+2+3=6

&

6/6=1 which means that it is divisible by 6

So,

$x^{3} +y^{3}+z^{3}=>1^{3}+2^{3}+3^{3}=>1+8+27=>36$

And 36 is divisible by 6

Hence proved

Hope it helps

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