Question

If x, y, z are three positive integers such that
x/y= 8, and y/z=1/6
and also x+z= 42, then the

value of y is given by:​

Answer 1

Answer:3

Step-by-step explanation:x=8y

z=6y

8y+6y=42

14y=42

y=3

Answer 2

Given :

x, y are positive integers such that

• x / y = 8
• y / z = 1 / 6
• x + z = 42

To find : Value of y

Solution :

Finding x in terms of y from x / y = 8

⇒ x / y = 8

⇒ x = 8y

Finding z in terms of y from y / z = 1 / 6

⇒ y / z = 1 / 6

⇒ y = z / 6

⇒ 6y = z

⇒ z = 6y

Substituting the values of x and z in x + z ✓ 42

⇒ x + z = 42

⇒ 8y + 6y = 42

⇒ 14y = 42

⇒ y = 42 / 14 = 3

Therefore the value of y is 3.