if x+y+z equal to 0 thenfind the value of x^3+y^3+8
Answers
Answered by
0
Answer:
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Step-by-step explanation:
x+y+z=0⇒x+y=−z
Cubing on both sides,
(x+y)
3
=(−z)
3
⇒x
3
+y
3
+3xy(x+y)=z
3
⇒x
3
+y
3
+3xy(−z)=−z
3
⇒x
3
+y
3
−3xyz+z
3
=0
∴x
3
+y
3
+z
3
=3xyz
Answered by
0
Answer:
x+y+z=0
x^3+y^3+2^3
z=2
x+y+z=0
(x+y+z)^3
=0^3
=0
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