If x=y+z find the value of x³-y³-z³-3xyz=?
Answers
Answered by
9
Answer:
Step-by-step explanation:
If x=y+z
Now,
X^3-y^3-z^3-3xyz
=Y^3+z^3 -y^3- z^3 -3×(y+z)×y×z
=-3 (y^2+yz ) ( yz +z^2)
=-3 (y+z)^2 (yz -yz)
=-3 × x^2
Similar questions