Math, asked by bhosale5738, 11 months ago

If x=y+z find the value of x³-y³-z³-3xyz=?

Answers

Answered by pappubangale1847
9

Answer:

Step-by-step explanation:

If x=y+z

Now,

X^3-y^3-z^3-3xyz

=Y^3+z^3 -y^3- z^3 -3×(y+z)×y×z

=-3 (y^2+yz ) ( yz +z^2)

=-3 (y+z)^2 (yz -yz)

=-3 × x^2

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