Math, asked by bhanukodati341, 7 days ago

If x,y,z > 0 such that x+2y+3z =15 ,then the minimum value of 6(1+x)yz+x(2y+3z) , is

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Answered by ramkrishandelhi1980

2

Answer:

that x+2y+3z =15 ,then the minimum value of 6(1+x)yz+x(2y+3z) ,

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