Question

if X + Y + Z is equal to 1, xy + yz plus zx is equal to -1 and x y z is equal to -1, find the value of x cube + y cube + Z cube

Answer 1

Answer:

hope u find it helpful

Step-by-step explanation:

hey mate here is ur answer

Answer 2

x³+y³+z³=1

Step-by-step explanation:

Given:

$x+y+z=1\\xy+yz+zx=-1\\xyz=-1$

$x+y+z=1$

Take cube on both sides

$(x+y+z)^{3} =1^{3}\\\\\Rightarrow x^{3} +y^{3}+z^{3}+3(x+y+z)(xy+yz+zx)-3xyz=1$

Substituting the given values:

$\Rightarrow x^{3} +y^{3}+z^{3}+3(1)(-1)-3\times (-1)=1\\\\\Rightarrow x^{3} +y^{3}+z^{3}-3+3=1\\\\\Rightarrow x^{3} +y^{3}+z^{3}=1$

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If x+1/x=3 then x^6+1/x^6=

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