if X + Y + Z is equal to 8 and xy + Y Z plus ZX equal to 20 find value of x squared plus y squared + Z Square
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Hi ,
x + y + z = 8-----( 1 )
xy + yz + zx = 20
Multiply each term with 2 , we get
2xy + 2yz + 2zx = 40 ---( 2 )
We know the algebraic identity ,
( x + y + z )² = x²+y²+z² + 2xy+2yz+2zx
8² = x² + y² + z² + 40 [ from ( 1 ) & ( 2 )]
64 - 40 = x² + y² + z²
Therefore,
x² + y² + z² = 24
I hope this helps you.
:)
x + y + z = 8-----( 1 )
xy + yz + zx = 20
Multiply each term with 2 , we get
2xy + 2yz + 2zx = 40 ---( 2 )
We know the algebraic identity ,
( x + y + z )² = x²+y²+z² + 2xy+2yz+2zx
8² = x² + y² + z² + 40 [ from ( 1 ) & ( 2 )]
64 - 40 = x² + y² + z²
Therefore,
x² + y² + z² = 24
I hope this helps you.
:)
rashmi1521:
its right
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