if X + Y + Z is equal to zero and X square + Y square + b square is equal to 12 find the value of xy + yz + xz
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Answer:
-6
Step-by-step explanation:
(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)
0=12+2(xy+yz+zx)
(xy+yz+zx)=-6
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