if x + y + z is equal to zero show that x cube + y cube + z cube is equal to 3 x y z
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given x+y+z=0 so according to the formula
x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
- x³+y³+z³-3xyz=0(x²+y²+z²-xy-yz-zx)
- x³+y³+z³-3xyz=0
- x³+y³+z³=0+3xyz
- x³+y³+z³=3xyz
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