Question

If x+y+z=,show that x^3+y^3+z^3=3xyz

Answer 1

Answer:

3xyz

Step-by-step explanation:

x³+y³+z³-3xyz=(X+y+z)(x²+y²+z²-xy-yz-zx)

if X+y+z=0 then,

x³+y³+z³-3xyz=0(x²+y²+z²-xy-yz-zx)

x³+y³+z³-3xyz=0

by transporting -3xyz to R.H.S.-

x³+y³+z³=3xyz

Answer 2

Answer:

3xyz

Step-by-step explanation:

3xyz is the answer hope it will helps you if yes then please thank my answer and please follow me and I will also follow you