if x+y+z show that x³+y³+z³
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Answer:
to prove , x³ + y³ + z³ = 3xyz
given
x + y + z = 0
=> x + y = - z
on cubing Both sides
( x + y)³ = ( -z )³
=> x ³ + y³ + 3xy( x + y) = - z³
=> x³ + y³ + 3xy.-z = -z³
=> x³ +y ³ - 3xyz = -z³
=> x³ + y³ + z³ = 3xyz.
Step-by-step explanation:
formula used " - ( a + b)³ = a³ + b³ + 3ab( a + b)
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