Question

if x=y=z then find the value of x^+y^+z^+2xy​

Answer 1

Answer:

Hence xyz=1 or 4*2*√2=8√2

Step-by-step explanation:

The above equations on taking logarithms to the base e gives

x*ln z=ln x…(1)

y*ln z=ln y…(2)

y*ln y=ln x…(3)

From equations (1) and (3) x*ln z=y*ln y and putting (2) in above eqn. we get

x*ln z=(y^2)*ln z giving x=y^2 or z=1.

For z=1, x= y=1

For x=y^2, putting x in (3)

y*ln y=ln y^2 =2*ln y or y=2. Hence x=2^2=4

Put value of y in (2) 2*ln z=ln 2 or z=√2

Hence xyz=1 or 4*2*√2=8√2