Question

If x=y+z then find the value of x3-y3-z3-3xyz

Answer 1

x = y + z

=> x + (-y) +(-z) = 0

[ By using the identity,

If a+b+c = 0

Then a^3 + b^3 + c^3 = 3abc]



x^3 - y^3 - z^3 = 3(x) (-y) (-z)

x^3 - y^3 - z^3 = 3xyz -------(1)

Now,

x^3 - y^3 - z^3 -3xyz = 3xyz - 3xyz = 0

Answer 2

x
$x = y + z = \\ x - y - z = 0$
x
$(x - y - z) {x }^{y {?}^{2}$