if x+y=z then find x3+y3-z3-3xyz
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Required Answer:-
Given:
- x + y = z
To find:
- x³ + y³ - z³ + 3xyz
Solution:
Given that,
➡ x + y = z
➡ x + y - z = 0
➡ x + y + (-z) = 0
We know that,
If a + b + c = 0,then a³ + b³ + c³ - 3abc = 0
Here, a = x, b = y, c = -z
So,
a³ + b³ + c³ - 3abc
= x³ + y³ - z³ - 3 × x × y × (-z)
= x³ + y³ - z³ + 3xyz
= 0
So,
x³ + y³ - z³ + 3xyz = 0 (Answer)
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