if x+y=z then prove that x3+y3+3xyz=z3
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x+y=z, (x+y)^3 =x^3 +y^3 +3xy(x+y)
substitute x+y =z , (z)^3=x^3 +y^3+ 3xy(z)
substitute x+y =z , (z)^3=x^3 +y^3+ 3xy(z)
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