Question

If x=y+z then x3-y3-z3- 3xyz=?

Answer 1

x = y+ z ,
x³-y³-z³ = 3xyz
(x+y)³ - y³ -z³= 3xyz
z³ +y³+3zy(y+z) - y³ -z³ = 3(y+z)yz
= 0 ans.

Answer 2

Answer:

The value of x³-y³-z³-3xyz=0

Step-by-step explanation:

Given x=y+z ----(1)

On Squaring equation (1) , we get

x³=(y+z)³

/* we know the algebraic identity,

$\boxed {(a+b)^{3}=a^{3}+b^{3}+3ab(a+b)}$

=> x³=y³+z³+3yz(y+z)

=> x³=y³+z³+3yzx /* From(1)*/

=> x³-y³-z³-3xyz = 0

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