If x=y=z then xy(x-y) + yz(y-z) + xz(z-x) =??
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Step-by-step explanation:
As it is given x=y=z
putting any one variable in place of othe two in the eqyation:
x²(x-x)+x²(x-x)+x²(x-x)
x²(0)+x²(0) + x²(0)= 0
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