Question

If (x^y)^z = x^y^z where each of x, y, and z is greater than 1, then find y in terms of z.
please answer me and no wrong answers​​

Answer 1

Answer:

Y = e ^ ln-Z/Z-1

Step-by-step explanation:

(X^Y) ^Z = X^Y^Z

YZ = Y^Z

Z = Y^Z/Y

Z = Y^Z-1

ln Z = (Z-1) ln Y

ln Y = ln Z/Z-1

Y = e ^ ln-Z/Z-1

Answer 2

y=e^log2

hope helps you make me as brainlist