if x +y+z=xyz then prove xy+yz+zx= 1
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this question is wrong....
let x=1
y=2
z=3
so first eq is
x+y+z=xyz
1+2+3=1×2×3
6=6
lhs=rhs
therefore,
xy+yz+xz=1×2+2×3+3×1
=2+6+3
=11
11≠1
LHS≠RHS
hence this equation is wrong
let x=1
y=2
z=3
so first eq is
x+y+z=xyz
1+2+3=1×2×3
6=6
lhs=rhs
therefore,
xy+yz+xz=1×2+2×3+3×1
=2+6+3
=11
11≠1
LHS≠RHS
hence this equation is wrong
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