if x+y = z
y+z = 3
x+z =y
then find
3xyz
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x + y = z ..... (1)
y + z = 3 ...... (2)
x + z = y ..... (3)
On adding (1), (2) and (3), we get
x + y + y + z + x + z = z + 3 + y
2x + 2y + 2z = z + 3 + y
2x + 2y - y + 2z - z = 3
2x + y + z = 3
2x + 3 = 3 ( from equation (2))
2x = 0
x = 0
If x = 0
Then
3xyz = 3yz × 0
= 0
y + z = 3 ...... (2)
x + z = y ..... (3)
On adding (1), (2) and (3), we get
x + y + y + z + x + z = z + 3 + y
2x + 2y + 2z = z + 3 + y
2x + 2y - y + 2z - z = 3
2x + y + z = 3
2x + 3 = 3 ( from equation (2))
2x = 0
x = 0
If x = 0
Then
3xyz = 3yz × 0
= 0
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0
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