Question

if x/(y+z)=y/(z+x)=z/(x+y) If so, then prove that the value of each ratio = 1/2 ​

Answer 1

Answer:

Case-1: If x + y + z 0, then

X+y + Z

Each ratio =x+y+z/ y + 2 + 2 + x + x + y

X+y +z/2y + 22 + 2x

x + y + z/2(y + z + x)

Cancel the common factor (x + y + z)

1 /2 !!

Case-2: If x + y + z = 0, then

y + z = -X

Then, the first ratio =x/y+z

X/-X-

Cancel the common factor -x

= -1

Hence, each ratio = -1.

X/y + z

(= -1

Hence, each ratio = 1.

Thus, the value of each ratio is1/ 2 or - 1.