Question

if x+y3z=0,then show that x³+y³+27z³=9xyz​

Answer 1

Step-by-step explanation:

x+y+3z=0

cubing both sides:

(x+y+3z)^3=0

x^3+y^3+27z^3-9xyz=0

x^3+y^3+27z^3=9xyz