Question

if x=ylog(xy)then dy/dx=?

Answer 1

x=y log y

dy/dx=d(y log y) /dx

dy/dx=y.d(log xy) /dx+log xy. dy/dx

dy/dx-log xy. dy/dx=xy.dy/dx+y(sq)

dy/dx(1-log xy-xy) =y(sq)

dy/dx=y(sq)/(1-log xy-xy)