If x + z = 2y and b2 = ac, then show that ay – z . bz – x . cx – y = 1.
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Step-by-step explanation:
x + z = 2y-----(1)
x-y=y-z-----(2)
b² = ac --( 3 )
LHS= a^(y-z) xb^(z - x) x c^(x - y)
= a^(x - y) x b^(z - x) x c^(x- y)
[from (2)]
= (ac)^( x - y) x b^(z - x)
= (b²)^(x - y) x b^ (z-x)
[From (3)]
= b^(2x - 2y) * b^(z - x)
= b^(2x - 2y +z - x)
= b^(x + z-2y)
= b^(2y-2y)
[From (1)]
= b^0
= 1
= RHS
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