Question

If x¹⁰⁰+100 is divided by x-1, then the remainder is ​

Answer 1

$p(x) = {x}^{100} + 100$

$g(x) = x - 1$

$g(x) = 0$

$x - 1 = 0$

$x = 1$

$p(1) = {1}^{100} + 100$

$p(1) = 1 + 100$

$p(1) = 101$

$the \: remainder \: is \: 101$