If x1/3+y1/3+z1/3=0 find the value of x+y+z
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the answer is 0.
x/3+y/3+z/3=0
1/3 (x+y+z)=0
x+y+z=3×0
x+y+z=0
x/3+y/3+z/3=0
1/3 (x+y+z)=0
x+y+z=3×0
x+y+z=0
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