If x1/3 + y1/3 + z1/3 = 0, then *
a) X3 + y3 + z3 = 0
(x+y+z)3 = 27xyz
x+y+z = 3xyz
x3 + y3 + z3 = 27xyz
Answers
Answered by
1
Answer:
x + y + z = 3xyz
hope it helps
Answered by
0
Answer:
If x1/3 + y1/3 + z1/3 = 0, then *
a) X3 + y3 + z3 = 0
(x+y+z)3 = 27xyz
x+y+z = 3xyz
x3 + y3 + z3 = 27xyz
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