Math, asked by akash84, 1 year ago

If x1/3+y1/3+z1/3= 0 then find the value of (x+y+z)3 .

Answers

Answered by naveenbrave

the answer to ur question is 0

Attachments:

akash84: A point lies on the x-axis at a distance of 7 units from the y-axis .What are its co-ordinates ? What will be the co-ordinates if it lies on y-axis at a distance of -7 units from x-axis?

naveenbrave: (7,0)

naveenbrave: (0,-7)

akash84: Simplify: [5{81/3 + 271/3}]1/4

akash84: pls answer

Answered by snehitha2

x(1/3)+y(1/3)+z(1/3)=0
x/3+y/3+z/3=0
(x+y+z)/3=0
Multiply 3/3 on both sides,
(x+y+z)/3×3/3=0×3/3
3(x+y+z)/9=0
3(x+y+z)=0

So,the answer is 0.

Hope it helps

akash84: Represent 13 on the number line.

akash84: Represent √13 on number line

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