Question

if x1/3+y1/3+z1/3=0 then find the value of (x+y+z)3

Answer 1

x(1/3)+y(1/3)+z(1/3)=0
x/3+y/3+z/3=0
(x+y+z)/3=0
Multiply 3/3 on both sides,
(x+y+z)/3×3/3=0×3/3
3(x+y+z)/9=0
3(x+y+z)=0

So,the answer is 0.

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