Question

If x1/3+y1/3+z1/3=0 then x+y+z=27xyz

Answer 1

Answer:

$\frac{x}{3} + \frac{y}{3} + \frac{z}{3} = 0 \\ \\ \frac{x + y + z}{3} = 0 \\ \\ x + y + z = 0 \\ \\ 27xyz = 0 \\ \\ xyz = \frac{0}{27} \\ \\ xyz = 0 \\ \\ x = 0 \\ \\ y = 0 \\ \\ z = 0. \\ answer$

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