If (x²+1)² = 3x², then prove that
x6+1=0
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Answer:
7
8
X²‐1+x
3x²‐4x+5
3x²+6x‐9
4x²‐17
8
X²‐1+x
3x²‐4x+5
3x²+6x‐9
4x²‐1
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