Question

If x2 + 1/3x2=k then prove that x6+1/27x6=k(k-1)(k+1)

Answer 1

9^2x = 27^(3x-2)

To solve for x, we will use the exponent properties to find x.

First we will rewrite the bases as powers of prime numbers.

We know that:

9 = 3^2

27 = 3^3

Let us substitute.

==> 3^2)^2x = (3^3)^(3x-2)

Now we know that x^a^b = x^ab

==> 3^(2*2x) = 3^(3*(3x-2)

==> 3^(4x) = 3^(9x-6)