If x2 – 1 is a factor of ax3 + bx2 + cx + d = 0, show that a + c = 0
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Step-by-step explanation:
ax3 + bx2 + cx + d = 0
x=1,-1
x=1,-1 are the zeroes of the polynomial
f(1)=a(1)+b(1)+c(1)+d=0
a+b+c+d=0
b+d= -(a+c)
f(-1)=a(-1)+b(1)+c(-1)+d=0
-a+b-c+d=0
we know that b+d=-(a+c)
-2(a+c)=0
(a+c)=0/-2
a+c=0
sasipriyankaj:
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how can -2(a+c)=0 become a+c =0 where is -2
0 by anything is 0
ok thank you
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