If x2-1 is a factor of ax4 + bx3 + x2 + dx +e show that a +c+e=b+d.
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Step-by-step explanation:
g{x}= x2 - 1
x2 - 1 = 0
x2 = 1
x = 1
f{x} = ax4+bx3+x2+dx+e
f{1} = a+b+1+d+e
a+b+1+d+e=0
a+1+e= -b-d
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