Question

if x2+1 upon x2 =27 then the value of x- 1 upon x is ​

Answer 1

hello refer to the attachment hope its help u

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Answer 2

x−x1

We have,

(x−x1)2=x2−2×x×x1+x21

⇒(x−x1)2=x2−2+x21

⇒(x−x1)2=x2+x21−2

⇒(x−x1)2=27−2[∵x2+x21=27 given]

⇒(x−x1)2=25⇒(x−x1)