if x²-1/x =1 , then prove that x⁶-1/x³=4
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x²-1/x=1
(x²-1/x)³=1³
x⁶-3x³-1/x³+3=1
x⁶-3x³-1/x³=-2
I got it till here, I'm not sure how 3x³-2 values as 4
Now if you see it like x⁶-1/x³=3x+1, x should be 1,
so that x⁶-1/x³=4 becomes true but in the given equation, it becomes x²-1/x=0, so I'm not sure you question is right
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